Gujarati
Hindi
4-1.Newton's Laws of Motion
medium

A man uses two pulleys to raise himself with an acceleration $2\,m/s^2$, as in figure. Man stands on a light weighing machine fitted on horizontal platform. Determine the  reading of weighing machine. Mass of man $= 75\, kg,$ mass of platform $= 25\, kg.$  ............ $N$

A$150$
B$300$
C$600$
D$900 $

Solution

$4 \mathrm{T}-100 \mathrm{g}=100 \mathrm{a}$
$\mathrm{T}=25(10+2)=300$
$FBD$ of man
$2 \mathrm{T}+\mathrm{N}-750=75 \times 2$
$2 \mathrm{T}+\mathrm{N}-750=150$
$\mathrm{N}=900-600=300 \mathrm{N}$
Standard 11
Physics

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